goodDays.js

/* You and a gang of thieves are planning on robbing a bank. You are given a 0-indexed integer array security, where security[i] is the number of guards on duty on the ith day. The days are numbered starting from 0. You are also given an integer time.

The ith day is a good day to rob the bank if:

There are at least time days before and after the ith day,
The number of guards at the bank for the time days before i are non-increasing, and
The number of guards at the bank for the time days after i are non-decreasing.
More formally, this means day i is a good day to rob the bank if and only if security[i - time] >= security[i - time + 1] >= ... >= security[i] <= ... <= security[i + time - 1] <= security[i + time].

Return a list of all days (0-indexed) that are good days to rob the bank. The order that the days are returned in does not matter.*/

const goodDaysToRobBank = function(security, time) {
    let result = [];
    for (let i = time; i + time < security.length; i++) {
      let bad = 0
      for (let j = i - time + 1; j <= i; j++)
        if (security[j - 1] < security[j]) {
          bad = 1; // increasing
          break
        }
      for (let j = i + 1; j <= i + time; j++)
        if (security[j - 1] > security[j]) {
          bad = 1; // decreasing
          break
        }
      if (!bad) {
        result.push(i)
      }
    }
    return result;
};